STAT3在双酚A促乳腺癌细胞增殖中的作用研究

目的:探讨STAT3在双酚A促乳腺癌MCF-7细胞增殖中的作用,为研究双酚A诱导乳腺癌的确切机制提供依据。方法:采用Western blot检测双酚A处理乳腺癌MCF-7细胞24 h和48 h后STAT3的表达情况,采用MTT法检测RNA干扰技术抑制STAT3后双酚A对乳腺癌细胞增殖的影响。结果:Western blot结果表明,STAT3在1μM双酚A作用48 h后其诱导表达最明显(P<0.05);通过对照研究筛选出有效的干扰片段,能显著抑制STAT3基因的表达,当干扰片段抑制了STAT3基因表达后,双酚A未能抑制STAT3的MCF-7细胞发生增殖效应(P>0.05)。结论:在双酚A诱导乳腺癌细胞的增殖作用中,STAT3的活化和活化后的信号传导是非常重要的一个环节。

Study on the effect of STAT3 in promotion of proliferation of breast cancer cells with bisphenol A

Objective:To explore the effect of STAT3 in promotion of proliferation of breast cancer cells with bisphenol A,and research the exact machanism of breast cancer induced by bisphenol A.Methods:Western blot was used to detect the expressions of STAT3 at 24 and 48 hours after treating breast cancer MCF-7 cells with bisphenol A,MTT method was used to detect the effect of bisphenol A on proliferation of breast cells after suppressing STAT3 with RNA interfering technique.Results:The results of Western blot showed that the inducing effect of STAT3 after treated with 1 μM bisphenol A for 48 hours was the most obvious(P<0.05);a case-control study was performed to screen out effective interfering fragments,which suppressed the expression of STAT3 gene significantly,when interfering fragments suppressed expression of STAT3 gene,bisphenol A didn't suppress the proliferative effect of STAT3 on breast cancer MCF-7 cells(P>0.05).Conclusion:The activation of STAT3 and signal transduction after activation is a very important link in proliferative effect of breast cancer cells induced by bisphenol A.